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\frac{\left(2\times 8+1\right)\times 2}{8\left(1\times 2+1\right)}
Divide \frac{2\times 8+1}{8} by \frac{1\times 2+1}{2} by multiplying \frac{2\times 8+1}{8} by the reciprocal of \frac{1\times 2+1}{2}.
\frac{1+2\times 8}{4\left(1+2\right)}
Cancel out 2 in both numerator and denominator.
\frac{1+16}{4\left(1+2\right)}
Multiply 2 and 8 to get 16.
\frac{17}{4\left(1+2\right)}
Add 1 and 16 to get 17.
\frac{17}{4\times 3}
Add 1 and 2 to get 3.
\frac{17}{12}
Multiply 4 and 3 to get 12.