Solve 21/4-11/3-1/8=

$$2 \frac { 1 } { 4 } - 1 \frac { 1 } { 3 } - \frac { 1 } { 8 } =$$

Evaluate

$$\frac{19}{24}\approx 0.791666667$$

Solution Steps

Multiply 2 and 4 to get 8.

$$\frac{8+1}{4}-\frac{1\times 3+1}{3}-\frac{1}{8}$$

Add 8 and 1 to get 9.

$$\frac{9}{4}-\frac{1\times 3+1}{3}-\frac{1}{8}$$

Multiply 1 and 3 to get 3.

$$\frac{9}{4}-\frac{3+1}{3}-\frac{1}{8}$$

Add 3 and 1 to get 4.

$$\frac{9}{4}-\frac{4}{3}-\frac{1}{8}$$

Least common multiple of 4 and 3 is 12. Convert \frac{9}{4} and \frac{4}{3} to fractions with denominator 12.

$$\frac{27}{12}-\frac{16}{12}-\frac{1}{8}$$

Since \frac{27}{12} and \frac{16}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{27-16}{12}-\frac{1}{8}$$

Subtract 16 from 27 to get 11.

$$\frac{11}{12}-\frac{1}{8}$$

Least common multiple of 12 and 8 is 24. Convert \frac{11}{12} and \frac{1}{8} to fractions with denominator 24.

$$\frac{22}{24}-\frac{3}{24}$$

Since \frac{22}{24} and \frac{3}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{22-3}{24}$$

Subtract 3 from 22 to get 19.

$$\frac{19}{24}$$

Factor

$$\frac{19}{2 ^ {3} \cdot 3} = 0.7916666666666666$$