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\frac{\left(2\times 4+1\right)\times 3}{4\times 2}
Divide \frac{2\times 4+1}{4} by \frac{2}{3} by multiplying \frac{2\times 4+1}{4} by the reciprocal of \frac{2}{3}.
\frac{\left(8+1\right)\times 3}{4\times 2}
Multiply 2 and 4 to get 8.
\frac{9\times 3}{4\times 2}
Add 8 and 1 to get 9.
\frac{27}{4\times 2}
Multiply 9 and 3 to get 27.
\frac{27}{8}
Multiply 4 and 2 to get 8.