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\frac{\left(2\times 2+1\right)\times 8}{2\left(4\times 8+3\right)}
Divide \frac{2\times 2+1}{2} by \frac{4\times 8+3}{8} by multiplying \frac{2\times 2+1}{2} by the reciprocal of \frac{4\times 8+3}{8}.
\frac{4\left(1+2\times 2\right)}{3+4\times 8}
Cancel out 2 in both numerator and denominator.
\frac{4\left(1+4\right)}{3+4\times 8}
Multiply 2 and 2 to get 4.
\frac{4\times 5}{3+4\times 8}
Add 1 and 4 to get 5.
\frac{20}{3+4\times 8}
Multiply 4 and 5 to get 20.
\frac{20}{3+32}
Multiply 4 and 8 to get 32.
\frac{20}{35}
Add 3 and 32 to get 35.
\frac{4}{7}
Reduce the fraction \frac{20}{35} to lowest terms by extracting and canceling out 5.