Solve 21/2+6(4+9)-416

$$2 \frac { 1 } { 2 } + 6 ( 4 + 9 ) - 416$$

Evaluate

$$-\frac{671}{2}=-335.5$$

Solution Steps

Multiply 2 and 2 to get 4.

$$\frac{4+1}{2}+6\left(4+9\right)-416$$

Add 4 and 1 to get 5.

$$\frac{5}{2}+6\left(4+9\right)-416$$

Add 4 and 9 to get 13.

$$\frac{5}{2}+6\times 13-416$$

Multiply 6 and 13 to get 78.

$$\frac{5}{2}+78-416$$

Convert 78 to fraction \frac{156}{2}.

$$\frac{5}{2}+\frac{156}{2}-416$$

Since \frac{5}{2} and \frac{156}{2} have the same denominator, add them by adding their numerators.

$$\frac{5+156}{2}-416$$

Add 5 and 156 to get 161.

$$\frac{161}{2}-416$$

Convert 416 to fraction \frac{832}{2}.

$$\frac{161}{2}-\frac{832}{2}$$

Since \frac{161}{2} and \frac{832}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{161-832}{2}$$

Subtract 832 from 161 to get -671.

$$-\frac{671}{2}$$

Factor

$$-\frac{671}{2} = -335\frac{1}{2} = -335.5$$