Solve 2cos(60^circ)+2cos(45^circ)-sin(90^circ)

$$2 \cos ( 60 ^ { \circ } ) +2 \cos ( 45 ^ { \circ } ) - \sin ( 90 ^ { \circ } )$$

Evaluate

$$\sqrt{2}\approx 1.414213562$$

Solution Steps

Get the value of \cos(60) from trigonometric values table.

$$2\times \frac{1}{2}+2\cos(45)-\sin(90)$$

Multiply 2 and \frac{1}{2} to get 1.

$$1+2\cos(45)-\sin(90)$$

Get the value of \cos(45) from trigonometric values table.

$$1+2\times \frac{\sqrt{2}}{2}-\sin(90)$$

Cancel out 2 and 2.

$$1+\sqrt{2}-\sin(90)$$

Get the value of \sin(90) from trigonometric values table.

$$1+\sqrt{2}-1$$

Subtract 1 from 1 to get 0.

$$\sqrt{2}$$