Solve 2*3^{5}-3*[3*3^2+4*3^5+2*(5*3^2-3*3^2)]

$$2 \cdot 3 ^ { 5 } - 3 \cdot [ 3 \cdot 3 ^ { 2 } + 4 \cdot 3 ^ { 5 } + 2 \cdot ( 5 \cdot 3 ^ { 2 } - 3 \cdot 3 ^ { 2 } ) ]$$

Evaluate

$$-2619$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2\times 3^{5}-3\left(3^{3}+4\times 3^{5}+2\left(5\times 3^{2}-3\times 3^{2}\right)\right)$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2\times 3^{5}-3\left(3^{3}+4\times 3^{5}+2\left(5\times 3^{2}-3^{3}\right)\right)$$

Calculate 3 to the power of 5 and get 243.

$$2\times 243-3\left(3^{3}+4\times 3^{5}+2\left(5\times 3^{2}-3^{3}\right)\right)$$

Multiply 2 and 243 to get 486.

$$486-3\left(3^{3}+4\times 3^{5}+2\left(5\times 3^{2}-3^{3}\right)\right)$$

Calculate 3 to the power of 3 and get 27.

$$486-3\left(27+4\times 3^{5}+2\left(5\times 3^{2}-3^{3}\right)\right)$$

Calculate 3 to the power of 5 and get 243.

$$486-3\left(27+4\times 243+2\left(5\times 3^{2}-3^{3}\right)\right)$$

Multiply 4 and 243 to get 972.

$$486-3\left(27+972+2\left(5\times 3^{2}-3^{3}\right)\right)$$

Add 27 and 972 to get 999.

$$486-3\left(999+2\left(5\times 3^{2}-3^{3}\right)\right)$$

Calculate 3 to the power of 2 and get 9.

$$486-3\left(999+2\left(5\times 9-3^{3}\right)\right)$$

Multiply 5 and 9 to get 45.

$$486-3\left(999+2\left(45-3^{3}\right)\right)$$

Calculate 3 to the power of 3 and get 27.

$$486-3\left(999+2\left(45-27\right)\right)$$

Subtract 27 from 45 to get 18.

$$486-3\left(999+2\times 18\right)$$

Multiply 2 and 18 to get 36.

$$486-3\left(999+36\right)$$

Add 999 and 36 to get 1035.

$$486-3\times 1035$$

Multiply 3 and 1035 to get 3105.

$$486-3105$$

Subtract 3105 from 486 to get -2619.

$$-2619$$

Factor

$$-2619$$