Solve 2*2^42*2*3*3*3*3=2^4*3

$$2 \cdot 2 ^ { 4 } 2 \cdot 2 \cdot 3 \cdot 3 \cdot 3 \cdot 3 = 2 ^ { 4 } \cdot 3$$

Verify

Solution Steps

Cancel out 3 on both sides.

$$2\times 2^{4}\times 2\times 2\times 3\times 3\times 3=2^{4}$$

To multiply powers of the same base, add their exponents. Add 1 and 4 to get 5.

$$2^{5}\times 2\times 2\times 3\times 3\times 3=2^{4}$$

To multiply powers of the same base, add their exponents. Add 5 and 1 to get 6.

$$2^{6}\times 2\times 3\times 3\times 3=2^{4}$$

To multiply powers of the same base, add their exponents. Add 6 and 1 to get 7.

$$2^{7}\times 3\times 3\times 3=2^{4}$$

Calculate 2 to the power of 7 and get 128.

$$128\times 3\times 3\times 3=2^{4}$$

Multiply 128 and 3 to get 384.

$$384\times 3\times 3=2^{4}$$

Multiply 384 and 3 to get 1152.

$$1152\times 3=2^{4}$$

Multiply 1152 and 3 to get 3456.

$$3456=2^{4}$$

Calculate 2 to the power of 4 and get 16.

$$3456=16$$

Compare 3456 and 16.

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