Solve 2*(1-x)=1-3y-x

$$2 \cdot ( 1 - x ) = 1 - 3 y - x$$

Solve for x

$$x=3y+1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by 1-x.

$$2-2x=1-3y-x$$

Add x to both sides.

$$2-2x+x=1-3y$$

Combine -2x and x to get -x.

$$2-x=1-3y$$

Subtract 2 from both sides.

$$-x=1-3y-2$$

Subtract 2 from 1 to get -1.

$$-x=-1-3y$$

The equation is in standard form.

$$-x=-3y-1$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{-3y-1}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{-3y-1}{-1}$$

Divide -1-3y by -1.

$$x=3y+1$$

Solve for y

$$y=\frac{x-1}{3}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by 1-x.

$$2-2x=1-3y-x$$

Swap sides so that all variable terms are on the left hand side.

$$1-3y-x=2-2x$$

Subtract 1 from both sides.

$$-3y-x=2-2x-1$$

Subtract 1 from 2 to get 1.

$$-3y-x=1-2x$$

Add x to both sides.

$$-3y=1-2x+x$$

Combine -2x and x to get -x.

$$-3y=1-x$$

Divide both sides by -3.

$$\frac{-3y}{-3}=\frac{1-x}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$y=\frac{1-x}{-3}$$

Divide 1-x by -3.

$$y=\frac{x-1}{3}$$