Solve 2*2-4^3--4^3+3(2)-2

$$2 \cdot 2 { -4 }^{ 3 } - { -4 }^{ 3 } +3(2)-2$$

Evaluate

$$-188$$

Solution Steps

Multiply 2 and 2 to get 4.

$$4\left(-4\right)^{3}-\left(-4\right)^{3}+3\times 2-2$$

Calculate -4 to the power of 3 and get -64.

$$4\left(-64\right)-\left(-4\right)^{3}+3\times 2-2$$

Multiply 4 and -64 to get -256.

$$-256-\left(-4\right)^{3}+3\times 2-2$$

Calculate -4 to the power of 3 and get -64.

$$-256-\left(-64\right)+3\times 2-2$$

The opposite of -64 is 64.

$$-256+64+3\times 2-2$$

Add -256 and 64 to get -192.

$$-192+3\times 2-2$$

Multiply 3 and 2 to get 6.

$$-192+6-2$$

Add -192 and 6 to get -186.

$$-186-2$$

Subtract 2 from -186 to get -188.

$$-188$$

Factor

$$-188$$