Solve 2{12div(-4)-[6-3(2-4*(-2)div2)]}

$$2 \{ 12 \div ( - 4 ) - [ 6 - 3 ( 2 - 4 \times ( - 2 ) \div 2 ) ] \}$$

Evaluate

$$18$$

Solution Steps

Divide 12 by -4 to get -3.

$$2\left(-3-\left(6-3\left(2-\frac{4\left(-2\right)}{2}\right)\right)\right)$$

Cancel out 2 and 2.

$$2\left(-3-\left(6-3\left(2-4\left(-1\right)\right)\right)\right)$$

Multiply 4 and -1 to get -4.

$$2\left(-3-\left(6-3\left(2-\left(-4\right)\right)\right)\right)$$

The opposite of -4 is 4.

$$2\left(-3-\left(6-3\left(2+4\right)\right)\right)$$

Add 2 and 4 to get 6.

$$2\left(-3-\left(6-3\times 6\right)\right)$$

Multiply 3 and 6 to get 18.

$$2\left(-3-\left(6-18\right)\right)$$

Subtract 18 from 6 to get -12.

$$2\left(-3-\left(-12\right)\right)$$

The opposite of -12 is 12.

$$2\left(-3+12\right)$$

Add -3 and 12 to get 9.

$$2\times 9$$

Multiply 2 and 9 to get 18.

$$18$$

Factor

$$2\times 3^{2}$$