Solve for x
x=\frac{y+2^{n}-1}{2}
Solve for n (complex solution)
n=\log_{2}\left(2x-y+1\right)+\frac{2\pi n_{1}i}{\ln(2)}
n_{1}\in \mathrm{Z}
x\neq \frac{y-1}{2}
Solve for n
n=\log_{2}\left(2x-y+1\right)
x>\frac{y-1}{2}
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2x-y=2^{n}-1
Swap sides so that all variable terms are on the left hand side.
2x=2^{n}-1+y
Add y to both sides.
2x=y+2^{n}-1
The equation is in standard form.
\frac{2x}{2}=\frac{y+2^{n}-1}{2}
Divide both sides by 2.
x=\frac{y+2^{n}-1}{2}
Dividing by 2 undoes the multiplication by 2.
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