Solve 2^{6}-2^{5}-2^4-2^3-2^2-2^1

$$2 ^ { 6 } - 2 ^ { 5 } - 2 ^ { 4 } - 2 ^ { 3 } - 2 ^ { 2 } - 2 ^ { 1 }$$

Evaluate

$$2$$

Solution Steps

Calculate 2 to the power of 6 and get 64.

$$64-2^{5}-2^{4}-2^{3}-2^{2}-2^{1}$$

Calculate 2 to the power of 5 and get 32.

$$64-32-2^{4}-2^{3}-2^{2}-2^{1}$$

Subtract 32 from 64 to get 32.

$$32-2^{4}-2^{3}-2^{2}-2^{1}$$

Calculate 2 to the power of 4 and get 16.

$$32-16-2^{3}-2^{2}-2^{1}$$

Subtract 16 from 32 to get 16.

$$16-2^{3}-2^{2}-2^{1}$$

Calculate 2 to the power of 3 and get 8.

$$16-8-2^{2}-2^{1}$$

Subtract 8 from 16 to get 8.

$$8-2^{2}-2^{1}$$

Calculate 2 to the power of 2 and get 4.

$$8-4-2^{1}$$

Subtract 4 from 8 to get 4.

$$4-2^{1}$$

Calculate 2 to the power of 1 and get 2.

$$4-2$$

Subtract 2 from 4 to get 2.

$$2$$

Factor

$$2$$