Solve for d
d=-\frac{3^{a}}{4}+4
Solve for a
a=\log_{3}\left(16-4d\right)
d<4
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16=3^{a}+4d
Calculate 2 to the power of 4 and get 16.
3^{a}+4d=16
Swap sides so that all variable terms are on the left hand side.
4d=16-3^{a}
Subtract 3^{a} from both sides.
\frac{4d}{4}=\frac{16-3^{a}}{4}
Divide both sides by 4.
d=\frac{16-3^{a}}{4}
Dividing by 4 undoes the multiplication by 4.
d=-\frac{3^{a}}{4}+4
Divide 16-3^{a} by 4.
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