Solve 2^3+3*(-2)-8:(-4)+sqrt[3]{-64}-sqrt[3]{2^3}

$$2 ^ { 3 } + 3 \cdot ( - 2 ) - 8 : ( - 4 ) + \sqrt[ 3 ] { - 64 } - \sqrt[ 3 ] { 2 ^ { 3 } }$$

Evaluate

$$-2$$

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$8+3\left(-2\right)-\frac{8}{-4}+\sqrt[3]{-64}-\sqrt[3]{2^{3}}$$

Multiply 3 and -2 to get -6.

$$8-6-\frac{8}{-4}+\sqrt[3]{-64}-\sqrt[3]{2^{3}}$$

Subtract 6 from 8 to get 2.

$$2-\frac{8}{-4}+\sqrt[3]{-64}-\sqrt[3]{2^{3}}$$

Divide 8 by -4 to get -2.

$$2-\left(-2\right)+\sqrt[3]{-64}-\sqrt[3]{2^{3}}$$

The opposite of -2 is 2.

$$2+2+\sqrt[3]{-64}-\sqrt[3]{2^{3}}$$

Add 2 and 2 to get 4.

$$4+\sqrt[3]{-64}-\sqrt[3]{2^{3}}$$

Calculate \sqrt[3]{-64} and get -4.

$$4-4-\sqrt[3]{2^{3}}$$

Subtract 4 from 4 to get 0.

$$0-\sqrt[3]{2^{3}}$$

Calculate 2 to the power of 3 and get 8.

$$0-\sqrt[3]{8}$$

Calculate \sqrt[3]{8} and get 2.

$$0-2$$

Subtract 2 from 0 to get -2.

$$-2$$

Factor

$$-2$$