Solve 2^3+10div2+5*3+4-5*2-8+4*7^2-16=2

$$2 ^ { 3 } + 10 \div 2 + 5 \times 3 + 4 - 5 \times 2 - 8 + 4 \times 7 ^ { 2 } - 16 = 2$$

Verify

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$8+\frac{10}{2}+5\times 3+4-5\times 2-8+4\times 7^{2}-16=2$$

Divide 10 by 2 to get 5.

$$8+5+5\times 3+4-5\times 2-8+4\times 7^{2}-16=2$$

Add 8 and 5 to get 13.

$$13+5\times 3+4-5\times 2-8+4\times 7^{2}-16=2$$

Multiply 5 and 3 to get 15.

$$13+15+4-5\times 2-8+4\times 7^{2}-16=2$$

Add 13 and 15 to get 28.

$$28+4-5\times 2-8+4\times 7^{2}-16=2$$

Add 28 and 4 to get 32.

$$32-5\times 2-8+4\times 7^{2}-16=2$$

Multiply 5 and 2 to get 10.

$$32-10-8+4\times 7^{2}-16=2$$

Subtract 10 from 32 to get 22.

$$22-8+4\times 7^{2}-16=2$$

Subtract 8 from 22 to get 14.

$$14+4\times 7^{2}-16=2$$

Calculate 7 to the power of 2 and get 49.

$$14+4\times 49-16=2$$

Multiply 4 and 49 to get 196.

$$14+196-16=2$$

Add 14 and 196 to get 210.

$$210-16=2$$

Subtract 16 from 210 to get 194.

$$194=2$$

Compare 194 and 2.

$$\text{false}$$