Solve 2^3+1/2*3/4-1=8

$$2 ^ { 3 } + \frac { 1 } { 2 } \cdot \frac { 3 } { 4 } - 1 = 8$$

Verify

Solution Steps

Calculate 2 to the power of 3 and get 8.

$$8+\frac{1}{2}\times \frac{3}{4}-1=8$$

Multiply \frac{1}{2} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$8+\frac{1\times 3}{2\times 4}-1=8$$

Do the multiplications in the fraction \frac{1\times 3}{2\times 4}.

$$8+\frac{3}{8}-1=8$$

Convert 8 to fraction \frac{64}{8}.

$$\frac{64}{8}+\frac{3}{8}-1=8$$

Since \frac{64}{8} and \frac{3}{8} have the same denominator, add them by adding their numerators.

$$\frac{64+3}{8}-1=8$$

Add 64 and 3 to get 67.

$$\frac{67}{8}-1=8$$

Convert 1 to fraction \frac{8}{8}.

$$\frac{67}{8}-\frac{8}{8}=8$$

Since \frac{67}{8} and \frac{8}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{67-8}{8}=8$$

Subtract 8 from 67 to get 59.

$$\frac{59}{8}=8$$

Convert 8 to fraction \frac{64}{8}.

$$\frac{59}{8}=\frac{64}{8}$$

Compare \frac{59}{8} and \frac{64}{8}.

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