Solve 2^2-14*(2*3)^2+49(3)^2-(2-7^2)

$$2 ^ { 2 } - 14 \times ( 2 \times 3 ) ^ { 2 } + 49 ( 3 ) ^ { 2 } - ( 2 - 7 ^ { 2 } )$$

Evaluate

$$-12$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$4-14\times \left(2\times 3\right)^{2}+49\times 3^{2}-\left(2-7^{2}\right)$$

Multiply 2 and 3 to get 6.

$$4-14\times 6^{2}+49\times 3^{2}-\left(2-7^{2}\right)$$

Calculate 6 to the power of 2 and get 36.

$$4-14\times 36+49\times 3^{2}-\left(2-7^{2}\right)$$

Multiply 14 and 36 to get 504.

$$4-504+49\times 3^{2}-\left(2-7^{2}\right)$$

Subtract 504 from 4 to get -500.

$$-500+49\times 3^{2}-\left(2-7^{2}\right)$$

Calculate 3 to the power of 2 and get 9.

$$-500+49\times 9-\left(2-7^{2}\right)$$

Multiply 49 and 9 to get 441.

$$-500+441-\left(2-7^{2}\right)$$

Add -500 and 441 to get -59.

$$-59-\left(2-7^{2}\right)$$

Calculate 7 to the power of 2 and get 49.

$$-59-\left(2-49\right)$$

Subtract 49 from 2 to get -47.

$$-59-\left(-47\right)$$

The opposite of -47 is 47.

$$-59+47$$

Add -59 and 47 to get -12.

$$-12$$

Factor

$$-12$$