Solve 2^{0}+2^{1}+2^{2}+2^3+2^4+2^5+2^6=

$$2 ^ { 0 } + 2 ^ { 1 } + 2 ^ { 2 } + 2 ^ { 3 } + 2 ^ { 4 } + 2 ^ { 5 } + 2 ^ { 6 } =$$

Evaluate

$$127$$

Solution Steps

Calculate 2 to the power of 0 and get 1.

$$1+2^{1}+2^{2}+2^{3}+2^{4}+2^{5}+2^{6}$$

Calculate 2 to the power of 1 and get 2.

$$1+2+2^{2}+2^{3}+2^{4}+2^{5}+2^{6}$$

Add 1 and 2 to get 3.

$$3+2^{2}+2^{3}+2^{4}+2^{5}+2^{6}$$

Calculate 2 to the power of 2 and get 4.

$$3+4+2^{3}+2^{4}+2^{5}+2^{6}$$

Add 3 and 4 to get 7.

$$7+2^{3}+2^{4}+2^{5}+2^{6}$$

Calculate 2 to the power of 3 and get 8.

$$7+8+2^{4}+2^{5}+2^{6}$$

Add 7 and 8 to get 15.

$$15+2^{4}+2^{5}+2^{6}$$

Calculate 2 to the power of 4 and get 16.

$$15+16+2^{5}+2^{6}$$

Add 15 and 16 to get 31.

$$31+2^{5}+2^{6}$$

Calculate 2 to the power of 5 and get 32.

$$31+32+2^{6}$$

Add 31 and 32 to get 63.

$$63+2^{6}$$

Calculate 2 to the power of 6 and get 64.

$$63+64$$

Add 63 and 64 to get 127.

$$127$$

Factor

$$127$$