Solve 2^0+(-2)^6*4^-1-(-2)^1

$$2 ^ { 0 } + ( - 2 ) ^ { 6 } \cdot 4 ^ { - 1 } - ( - 2 ) ^ { 1 }$$

Evaluate

$$19$$

Solution Steps

Calculate 2 to the power of 0 and get 1.

$$1+\left(-2\right)^{6}\times 4^{-1}-\left(-2\right)^{1}$$

Calculate -2 to the power of 6 and get 64.

$$1+64\times 4^{-1}-\left(-2\right)^{1}$$

Calculate 4 to the power of -1 and get \frac{1}{4}.

$$1+64\times \frac{1}{4}-\left(-2\right)^{1}$$

Multiply 64 and \frac{1}{4} to get 16.

$$1+16-\left(-2\right)^{1}$$

Add 1 and 16 to get 17.

$$17-\left(-2\right)^{1}$$

Calculate -2 to the power of 1 and get -2.

$$17-\left(-2\right)$$

The opposite of -2 is 2.

$$17+2$$

Add 17 and 2 to get 19.

$$19$$

Factor

$$19$$