Solve 2^-2*7^0-(7^2)^2

$$2 ^ { - 2 } \cdot 7 ^ { 0 } - ( 7 ^ { 2 } ) ^ { 2 }$$

Evaluate

$$-\frac{9603}{4}=-2400.75$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$2^{-2}\times 7^{0}-7^{4}$$

Calculate 2 to the power of -2 and get \frac{1}{4}.

$$\frac{1}{4}\times 7^{0}-7^{4}$$

Calculate 7 to the power of 0 and get 1.

$$\frac{1}{4}\times 1-7^{4}$$

Multiply \frac{1}{4} and 1 to get \frac{1}{4}.

$$\frac{1}{4}-7^{4}$$

Calculate 7 to the power of 4 and get 2401.

$$\frac{1}{4}-2401$$

Subtract 2401 from \frac{1}{4} to get -\frac{9603}{4}.

$$-\frac{9603}{4}$$

Factor

$$-\frac{9603}{4} = -2400\frac{3}{4} = -2400.75$$