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\frac{1}{2}+|-3|\times 2^{0}-\sqrt{\frac{1}{4}}
Calculate 2 to the power of -1 and get \frac{1}{2}.
\frac{1}{2}+3\times 2^{0}-\sqrt{\frac{1}{4}}
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -3 is 3.
\frac{1}{2}+3\times 1-\sqrt{\frac{1}{4}}
Calculate 2 to the power of 0 and get 1.
\frac{1}{2}+3-\sqrt{\frac{1}{4}}
Multiply 3 and 1 to get 3.
\frac{7}{2}-\sqrt{\frac{1}{4}}
Add \frac{1}{2} and 3 to get \frac{7}{2}.
\frac{7}{2}-\frac{1}{2}
Rewrite the square root of the division \frac{1}{4} as the division of square roots \frac{\sqrt{1}}{\sqrt{4}}. Take the square root of both numerator and denominator.
3
Subtract \frac{1}{2} from \frac{7}{2} to get 3.