Solve 2=r^3-3rl

$$2 = r ^ { 3 } - 3 r l$$

Solve for l

$$l=\frac{r^{3}-2}{3r}$$

$$r\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$r^{3}-3rl=2$$

Subtract r^{3} from both sides.

$$-3rl=2-r^{3}$$

The equation is in standard form.

$$\left(-3r\right)l=2-r^{3}$$

Divide both sides by -3r.

$$\frac{\left(-3r\right)l}{-3r}=\frac{2-r^{3}}{-3r}$$

Dividing by -3r undoes the multiplication by -3r.

$$l=\frac{2-r^{3}}{-3r}$$

Divide 2-r^{3} by -3r.

$$l=\frac{r^{2}}{3}-\frac{2}{3r}$$