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\frac{2\sqrt{7}}{\left(\sqrt{7}\right)^{2}}-\sqrt{54}
Rationalize the denominator of \frac{2}{\sqrt{7}} by multiplying numerator and denominator by \sqrt{7}.
\frac{2\sqrt{7}}{7}-\sqrt{54}
The square of \sqrt{7} is 7.
\frac{2\sqrt{7}}{7}-3\sqrt{6}
Factor 54=3^{2}\times 6. Rewrite the square root of the product \sqrt{3^{2}\times 6} as the product of square roots \sqrt{3^{2}}\sqrt{6}. Take the square root of 3^{2}.
\frac{2\sqrt{7}}{7}+\frac{7\left(-3\right)\sqrt{6}}{7}
To add or subtract expressions, expand them to make their denominators the same. Multiply -3\sqrt{6} times \frac{7}{7}.
\frac{2\sqrt{7}+7\left(-3\right)\sqrt{6}}{7}
Since \frac{2\sqrt{7}}{7} and \frac{7\left(-3\right)\sqrt{6}}{7} have the same denominator, add them by adding their numerators.
\frac{2\sqrt{7}-21\sqrt{6}}{7}
Do the multiplications in 2\sqrt{7}+7\left(-3\right)\sqrt{6}.