Solve 2,(2-sqrt{2})*(2+sqrt{2})

$$2 , ( 2 - \sqrt { 2 } ) \cdot ( 2 + \sqrt { 2 } )$$

Sort

$$2,2$$

Solution Steps

Consider \left(2-\sqrt{2}\right)\left(2+\sqrt{2}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.

$$sort(2,2^{2}-\left(\sqrt{2}\right)^{2})$$

Calculate 2 to the power of 2 and get 4.

$$sort(2,4-\left(\sqrt{2}\right)^{2})$$

The square of \sqrt{2} is 2.

$$sort(2,4-2)$$

Subtract 2 from 4 to get 2.

$$sort(2,2)$$

The list values are already in order.

$$2,2$$

Evaluate

$$2,2$$