Solve 2+3x+5+6x-12-4x-10-2x-7<10

$$2 + 3 x + 5 + 6 x - 12 - 4 x - 10 - 2 x - 7 < 10$$

Solve for x

$$x<\frac{32}{3}$$

Solution Steps

Add 2 and 5 to get 7.

$$7+3x+6x-12-4x-10-2x-7<10$$

Combine 3x and 6x to get 9x.

$$7+9x-12-4x-10-2x-7<10$$

Subtract 12 from 7 to get -5.

$$-5+9x-4x-10-2x-7<10$$

Combine 9x and -4x to get 5x.

$$-5+5x-10-2x-7<10$$

Subtract 10 from -5 to get -15.

$$-15+5x-2x-7<10$$

Combine 5x and -2x to get 3x.

$$-15+3x-7<10$$

Subtract 7 from -15 to get -22.

$$-22+3x<10$$

Add 22 to both sides.

$$3x<10+22$$

Add 10 and 22 to get 32.

$$3x<32$$

Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$x<\frac{32}{3}$$