Solve 2+3(b+1)-(b+1)*3-2b=0

$$2 + 3 ( b + 1 ) - ( b + 1 ) \cdot 3 - 2 b = 0$$

Solve for b

$$b=1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by b+1.

$$2+3b+3-\left(b+1\right)\times 3-2b=0$$

Add 2 and 3 to get 5.

$$5+3b-\left(b+1\right)\times 3-2b=0$$

Use the distributive property to multiply b+1 by 3.

$$5+3b-\left(3b+3\right)-2b=0$$

To find the opposite of 3b+3, find the opposite of each term.

$$5+3b-3b-3-2b=0$$

Combine 3b and -3b to get 0.

$$5-3-2b=0$$

Subtract 3 from 5 to get 2.

$$2-2b=0$$

Subtract 2 from both sides. Anything subtracted from zero gives its negation.

$$-2b=-2$$

Divide both sides by -2.

$$b=\frac{-2}{-2}$$

Divide -2 by -2 to get 1.

$$b=1$$