Solve 211/15+16/20

$$2 \frac { 11 } { 15 } + 1 \frac { 6 } { 20 }$$

Evaluate

$$\frac{121}{30}\approx 4.033333333$$

Solution Steps

Multiply 2 and 15 to get 30.

$$\frac{30+11}{15}+\frac{1\times 20+6}{20}$$

Add 30 and 11 to get 41.

$$\frac{41}{15}+\frac{1\times 20+6}{20}$$

Multiply 1 and 20 to get 20.

$$\frac{41}{15}+\frac{20+6}{20}$$

Add 20 and 6 to get 26.

$$\frac{41}{15}+\frac{26}{20}$$

Reduce the fraction \frac{26}{20} to lowest terms by extracting and canceling out 2.

$$\frac{41}{15}+\frac{13}{10}$$

Least common multiple of 15 and 10 is 30. Convert \frac{41}{15} and \frac{13}{10} to fractions with denominator 30.

$$\frac{82}{30}+\frac{39}{30}$$

Since \frac{82}{30} and \frac{39}{30} have the same denominator, add them by adding their numerators.

$$\frac{82+39}{30}$$

Add 82 and 39 to get 121.

$$\frac{121}{30}$$

Factor

$$\frac{11 ^ {2}}{2 \cdot 3 \cdot 5} = 4\frac{1}{30} = 4.033333333333333$$