Solve 195cz+255z=z

$$195 c z + 255 z = z$$

Solve for c

$$\left\{\begin{matrix}\\c=-\frac{254}{195}\approx -1.302564103\text{, }&\text{unconditionally}\\c\in \mathrm{R}\text{, }&z=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 255z from both sides.

$$195cz=z-255z$$

Combine z and -255z to get -254z.

$$195cz=-254z$$

The equation is in standard form.

$$195zc=-254z$$

Divide both sides by 195z.

$$\frac{195zc}{195z}=-\frac{254z}{195z}$$

Dividing by 195z undoes the multiplication by 195z.

$$c=-\frac{254z}{195z}$$

Divide -254z by 195z.

$$c=-\frac{254}{195}$$

Solve for z

$$\left\{\begin{matrix}\\z=0\text{, }&\text{unconditionally}\\z\in \mathrm{R}\text{, }&c=-\frac{254}{195}\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract z from both sides.

$$195cz+255z-z=0$$

Combine 255z and -z to get 254z.

$$195cz+254z=0$$

Combine all terms containing z.

$$\left(195c+254\right)z=0$$

Divide 0 by 254+195c.

$$z=0$$