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19x^{2}+60x-173=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-60±\sqrt{60^{2}-4\times 19\left(-173\right)}}{2\times 19}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-60±\sqrt{3600-4\times 19\left(-173\right)}}{2\times 19}
Square 60.
x=\frac{-60±\sqrt{3600-76\left(-173\right)}}{2\times 19}
Multiply -4 times 19.
x=\frac{-60±\sqrt{3600+13148}}{2\times 19}
Multiply -76 times -173.
x=\frac{-60±\sqrt{16748}}{2\times 19}
Add 3600 to 13148.
x=\frac{-60±2\sqrt{4187}}{2\times 19}
Take the square root of 16748.
x=\frac{-60±2\sqrt{4187}}{38}
Multiply 2 times 19.
x=\frac{2\sqrt{4187}-60}{38}
Now solve the equation x=\frac{-60±2\sqrt{4187}}{38} when ± is plus. Add -60 to 2\sqrt{4187}.
x=\frac{\sqrt{4187}-30}{19}
Divide -60+2\sqrt{4187} by 38.
x=\frac{-2\sqrt{4187}-60}{38}
Now solve the equation x=\frac{-60±2\sqrt{4187}}{38} when ± is minus. Subtract 2\sqrt{4187} from -60.
x=\frac{-\sqrt{4187}-30}{19}
Divide -60-2\sqrt{4187} by 38.
19x^{2}+60x-173=19\left(x-\frac{\sqrt{4187}-30}{19}\right)\left(x-\frac{-\sqrt{4187}-30}{19}\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{-30+\sqrt{4187}}{19} for x_{1} and \frac{-30-\sqrt{4187}}{19} for x_{2}.
x ^ 2 +\frac{60}{19}x -\frac{173}{19} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 19
r + s = -\frac{60}{19} rs = -\frac{173}{19}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -\frac{30}{19} - u s = -\frac{30}{19} + u
Two numbers r and s sum up to -\frac{60}{19} exactly when the average of the two numbers is \frac{1}{2}*-\frac{60}{19} = -\frac{30}{19}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-\frac{30}{19} - u) (-\frac{30}{19} + u) = -\frac{173}{19}
To solve for unknown quantity u, substitute these in the product equation rs = -\frac{173}{19}
\frac{900}{361} - u^2 = -\frac{173}{19}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -\frac{173}{19}-\frac{900}{361} = -\frac{4187}{361}
Simplify the expression by subtracting \frac{900}{361} on both sides
u^2 = \frac{4187}{361} u = \pm\sqrt{\frac{4187}{361}} = \pm \frac{\sqrt{4187}}{19}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-\frac{30}{19} - \frac{\sqrt{4187}}{19} = -4.985 s = -\frac{30}{19} + \frac{\sqrt{4187}}{19} = 1.827
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.