Solve 19+2-(71)/50|3=

$$19 + \frac { 2 - ( 71 ) } { 50 } | 3 =$$

Evaluate

$$\frac{743}{50}=14.86$$

Solution Steps

Subtract 71 from 2 to get -69.

$$19+\frac{-69}{50}|3|$$

Fraction \frac{-69}{50} can be rewritten as -\frac{69}{50} by extracting the negative sign.

$$19-\frac{69}{50}|3|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 3 is 3.

$$19-\frac{69}{50}\times 3$$

Express -\frac{69}{50}\times 3 as a single fraction.

$$19+\frac{-69\times 3}{50}$$

Multiply -69 and 3 to get -207.

$$19+\frac{-207}{50}$$

Fraction \frac{-207}{50} can be rewritten as -\frac{207}{50} by extracting the negative sign.

$$19-\frac{207}{50}$$

Convert 19 to fraction \frac{950}{50}.

$$\frac{950}{50}-\frac{207}{50}$$

Since \frac{950}{50} and \frac{207}{50} have the same denominator, subtract them by subtracting their numerators.

$$\frac{950-207}{50}$$

Subtract 207 from 950 to get 743.

$$\frac{743}{50}$$

Factor

$$\frac{743}{2 \cdot 5 ^ {2}} = 14\frac{43}{50} = 14.86$$