Solve 1800+50x<2040+42*5x

$$1800+50x < 2040+42 \cdot 5x$$

Solve for x

$$x>-\frac{3}{2}$$

Solution Steps

Multiply 42 and 5 to get 210.

$$1800+50x<2040+210x$$

Subtract 210x from both sides.

$$1800+50x-210x<2040$$

Combine 50x and -210x to get -160x.

$$1800-160x<2040$$

Subtract 1800 from both sides.

$$-160x<2040-1800$$

Subtract 1800 from 2040 to get 240.

$$-160x<240$$

Divide both sides by -160. Since -160 is negative, the inequality direction is changed.

$$x>\frac{240}{-160}$$

Reduce the fraction \frac{240}{-160} to lowest terms by extracting and canceling out 80.

$$x>-\frac{3}{2}$$