Solve 18{left(1/3right)}^3+1/3-1

$$18 { \left( \frac{ 1 }{ 3 } \right) }^{ 3 } + \frac{ 1 }{ 3 } -1$$

Evaluate

$$0$$

Solution Steps

Calculate \frac{1}{3} to the power of 3 and get \frac{1}{27}.

$$18\times \frac{1}{27}+\frac{1}{3}-1$$

Multiply 18 and \frac{1}{27} to get \frac{18}{27}.

$$\frac{18}{27}+\frac{1}{3}-1$$

Reduce the fraction \frac{18}{27} to lowest terms by extracting and canceling out 9.

$$\frac{2}{3}+\frac{1}{3}-1$$

Since \frac{2}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{2+1}{3}-1$$

Add 2 and 1 to get 3.

$$\frac{3}{3}-1$$

Divide 3 by 3 to get 1.

$$1-1$$

Subtract 1 from 1 to get 0.

$$0$$

Factor

$$0$$