Solve 18*(1/6+1/3-1/2)

$$18 \times ( \frac { 1 } { 6 } + \frac { 1 } { 3 } - \frac { 1 } { 2 } )$$

Evaluate

$$0$$

Solution Steps

Least common multiple of 6 and 3 is 6. Convert \frac{1}{6} and \frac{1}{3} to fractions with denominator 6.

$$18\left(\frac{1}{6}+\frac{2}{6}-\frac{1}{2}\right)$$

Since \frac{1}{6} and \frac{2}{6} have the same denominator, add them by adding their numerators.

$$18\left(\frac{1+2}{6}-\frac{1}{2}\right)$$

Add 1 and 2 to get 3.

$$18\left(\frac{3}{6}-\frac{1}{2}\right)$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$18\left(\frac{1}{2}-\frac{1}{2}\right)$$

Subtract \frac{1}{2} from \frac{1}{2} to get 0.

$$18\times 0$$

Multiply 18 and 0 to get 0.

$$0$$

Factor

$$0$$