Solve 18*10^-2*(10^-2+1)

$$18 \cdot 10 ^ { - 2 } \cdot ( 10 ^ { - 2 } + 1 )$$

Evaluate

$$\frac{909}{5000}=0.1818$$

Solution Steps

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$18\times \frac{1}{100}\left(10^{-2}+1\right)$$

Multiply 18 and \frac{1}{100} to get \frac{9}{50}.

$$\frac{9}{50}\left(10^{-2}+1\right)$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$\frac{9}{50}\left(\frac{1}{100}+1\right)$$

Add \frac{1}{100} and 1 to get \frac{101}{100}.

$$\frac{9}{50}\times \frac{101}{100}$$

Multiply \frac{9}{50} and \frac{101}{100} to get \frac{909}{5000}.

$$\frac{909}{5000}$$

Factor

$$\frac{3 ^ {2} \cdot 101}{2 ^ {3} \cdot 5 ^ {4}} = 0.1818$$