Factor
2\left(2y+5\right)\left(4y^{2}-10y+25\right)
Evaluate
16y^{3}+250
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2\left(8y^{3}+125\right)
Factor out 2.
\left(2y+5\right)\left(4y^{2}-10y+25\right)
Consider 8y^{3}+125. Rewrite 8y^{3}+125 as \left(2y\right)^{3}+5^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
2\left(2y+5\right)\left(4y^{2}-10y+25\right)
Rewrite the complete factored expression. Polynomial 4y^{2}-10y+25 is not factored since it does not have any rational roots.
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