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4x^{2}\left(4x+5\right)-25\left(4x+5\right)
Do the grouping 16x^{3}+20x^{2}-100x-125=\left(16x^{3}+20x^{2}\right)+\left(-100x-125\right), and factor out 4x^{2} in the first and -25 in the second group.
\left(4x+5\right)\left(4x^{2}-25\right)
Factor out common term 4x+5 by using distributive property.
\left(2x-5\right)\left(2x+5\right)
Consider 4x^{2}-25. Rewrite 4x^{2}-25 as \left(2x\right)^{2}-5^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\left(2x-5\right)\left(2x+5\right)\left(4x+5\right)
Rewrite the complete factored expression.