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\left(4x-3y-8\right)\left(4x-3y+8\right)
Rewrite 16x^{2}-24xy-64+9y^{2} as \left(4x-3y\right)^{2}-8^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).