Solve 16x^12-24x^0+9

$$16 x ^ { 12 } - 24 x ^ { 0 } + 9$$

Evaluate

$$16x^{12}-15$$

Solution Steps

Calculate x to the power of 0 and get 1.

$$16x^{12}-24+9$$

Add -24 and 9 to get -15.

$$16x^{12}-15$$

Differentiate w.r.t. x

$$192x^{11}$$

Steps Using Derivative Rule for Sum

Calculate x to the power of 0 and get 1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(16x^{12}-24+9)$$

Add -24 and 9 to get -15.

$$\frac{\mathrm{d}}{\mathrm{d}x}(16x^{12}-15)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$12\times 16x^{12-1}$$

Multiply 12 times 16.

$$192x^{12-1}$$

Subtract 1 from 12.

$$192x^{11}$$