Solve for a
a=-\frac{c}{16}-\frac{3b}{8}+\frac{1}{8}
Solve for b
b=-\frac{c}{6}-\frac{8a}{3}+\frac{1}{3}
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16a+c=2-6b
Subtract 6b from both sides.
16a=2-6b-c
Subtract c from both sides.
16a=2-c-6b
The equation is in standard form.
\frac{16a}{16}=\frac{2-c-6b}{16}
Divide both sides by 16.
a=\frac{2-c-6b}{16}
Dividing by 16 undoes the multiplication by 16.
a=-\frac{c}{16}-\frac{3b}{8}+\frac{1}{8}
Divide 2-6b-c by 16.
6b+c=2-16a
Subtract 16a from both sides.
6b=2-16a-c
Subtract c from both sides.
6b=2-c-16a
The equation is in standard form.
\frac{6b}{6}=\frac{2-c-16a}{6}
Divide both sides by 6.
b=\frac{2-c-16a}{6}
Dividing by 6 undoes the multiplication by 6.
b=-\frac{c}{6}-\frac{8a}{3}+\frac{1}{3}
Divide 2-16a-c by 6.
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