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-x^{2}=1-16
Subtract 16 from both sides.
-x^{2}=-15
Subtract 16 from 1 to get -15.
x^{2}=\frac{-15}{-1}
Divide both sides by -1.
x^{2}=15
Fraction \frac{-15}{-1} can be simplified to 15 by removing the negative sign from both the numerator and the denominator.
x=\sqrt{15} x=-\sqrt{15}
Take the square root of both sides of the equation.
16-x^{2}-1=0
Subtract 1 from both sides.
15-x^{2}=0
Subtract 1 from 16 to get 15.
-x^{2}+15=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-1\right)\times 15}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 0 for b, and 15 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-1\right)\times 15}}{2\left(-1\right)}
Square 0.
x=\frac{0±\sqrt{4\times 15}}{2\left(-1\right)}
Multiply -4 times -1.
x=\frac{0±\sqrt{60}}{2\left(-1\right)}
Multiply 4 times 15.
x=\frac{0±2\sqrt{15}}{2\left(-1\right)}
Take the square root of 60.
x=\frac{0±2\sqrt{15}}{-2}
Multiply 2 times -1.
x=-\sqrt{15}
Now solve the equation x=\frac{0±2\sqrt{15}}{-2} when ± is plus.
x=\sqrt{15}
Now solve the equation x=\frac{0±2\sqrt{15}}{-2} when ± is minus.
x=-\sqrt{15} x=\sqrt{15}
The equation is now solved.