Solve 16(x+1)^2=49

$$16 ( x + 1 ) ^ { 2 } = 49$$

Solve for x

$$x=\frac{3}{4}=0.75$$

$$x = -\frac{11}{4} = -2\frac{3}{4} = -2.75$$

Steps by Finding Square Root

Divide both sides by 16.

$$\frac{16\left(x+1\right)^{2}}{16}=\frac{49}{16}$$

Dividing by 16 undoes the multiplication by 16.

$$\left(x+1\right)^{2}=\frac{49}{16}$$

Take the square root of both sides of the equation.

$$x+1=\frac{7}{4} x+1=-\frac{7}{4}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{7}{4}-1 x+1-1=-\frac{7}{4}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{7}{4}-1 x=-\frac{7}{4}-1$$

Subtract 1 from \frac{7}{4}.

$$x=\frac{3}{4}$$

Subtract 1 from -\frac{7}{4}.

$$x=-\frac{11}{4}$$

The equation is now solved.

$$x=\frac{3}{4} x=-\frac{11}{4}$$