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2\left(8x^{6}-125y^{3}\right)
Factor out 2.
\left(2x^{2}-5y\right)\left(4x^{4}+25y^{2}+10yx^{2}\right)
Consider 8x^{6}-125y^{3}. Rewrite 8x^{6}-125y^{3} as \left(2x^{2}\right)^{3}-\left(5y\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
2\left(2x^{2}-5y\right)\left(4x^{4}+25y^{2}+10yx^{2}\right)
Rewrite the complete factored expression.