Factor
\left(2x-3\right)\left(2x+1\right)^{3}
Evaluate
\left(2x-3\right)\left(2x+1\right)^{3}
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\left(2x-3\right)\left(8x^{3}+12x^{2}+6x+1\right)
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -3 and q divides the leading coefficient 16. One such root is \frac{3}{2}. Factor the polynomial by dividing it by 2x-3.
\left(2x+1\right)^{3}
Consider 8x^{3}+12x^{2}+6x+1. Use the binomial cube formula, a^{3}+3a^{2}b+3ab^{2}+b^{3}=\left(a+b\right)^{3}, where a=2x and b=1.
\left(2x-3\right)\left(2x+1\right)^{3}
Rewrite the complete factored expression.
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y = 3x + 4
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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