Solve 16x^2+7x+81

$$16 { x }^{ 2 } +7x+81$$

Differentiate w.r.t. x

$$32x+7$$

Steps Using Derivative Rule for Sum

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2\times 16x^{2-1}+7x^{1-1}$$

Multiply 2 times 16.

$$32x^{2-1}+7x^{1-1}$$

Subtract 1 from 2.

$$32x^{1}+7x^{1-1}$$

Subtract 1 from 1.

$$32x^{1}+7x^{0}$$

For any term t, t^{1}=t.

$$32x+7x^{0}$$

For any term t except 0, t^{0}=1.

$$32x+7\times 1$$

For any term t, t\times 1=t and 1t=t.

$$32x+7$$

Evaluate

$$16x^{2}+7x+81$$