Solve 16x^2+32x=273

$$16 { x }^{ 2 } +32x=273$$

Solve for x

$$x = -\frac{21}{4} = -5\frac{1}{4} = -5.25$$

$$x = \frac{13}{4} = 3\frac{1}{4} = 3.25$$

Steps Using Factoring By Grouping

Subtract 273 from both sides.

$$16x^{2}+32x-273=0$$

To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as 16x^{2}+ax+bx-273. To find a and b, set up a system to be solved.

$$a+b=32 ab=16\left(-273\right)=-4368$$

Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -4368.

$$-1,4368 -2,2184 -3,1456 -4,1092 -6,728 -7,624 -8,546 -12,364 -13,336 -14,312 -16,273 -21,208 -24,182 -26,168 -28,156 -39,112 -42,104 -48,91 -52,84 -56,78$$

Calculate the sum for each pair.

$$-1+4368=4367 -2+2184=2182 -3+1456=1453 -4+1092=1088 -6+728=722 -7+624=617 -8+546=538 -12+364=352 -13+336=323 -14+312=298 -16+273=257 -21+208=187 -24+182=158 -26+168=142 -28+156=128 -39+112=73 -42+104=62 -48+91=43 -52+84=32 -56+78=22$$

The solution is the pair that gives sum 32.

$$a=-52 b=84$$

Rewrite 16x^{2}+32x-273 as \left(16x^{2}-52x\right)+\left(84x-273\right).

$$\left(16x^{2}-52x\right)+\left(84x-273\right)$$

Factor out 4x in the first and 21 in the second group.

$$4x\left(4x-13\right)+21\left(4x-13\right)$$

Factor out common term 4x-13 by using distributive property.

$$\left(4x-13\right)\left(4x+21\right)$$

To find equation solutions, solve 4x-13=0 and 4x+21=0.

$$x=\frac{13}{4} x=-\frac{21}{4}$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$16x^{2}+32x=273$$

Subtract 273 from both sides of the equation.

$$16x^{2}+32x-273=273-273$$

Subtracting 273 from itself leaves 0.

$$16x^{2}+32x-273=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 16 for a, 32 for b, and -273 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-32±\sqrt{32^{2}-4\times 16\left(-273\right)}}{2\times 16}$$

Square 32.

$$x=\frac{-32±\sqrt{1024-4\times 16\left(-273\right)}}{2\times 16}$$

Multiply -4 times 16.

$$x=\frac{-32±\sqrt{1024-64\left(-273\right)}}{2\times 16}$$

Multiply -64 times -273.

$$x=\frac{-32±\sqrt{1024+17472}}{2\times 16}$$

Add 1024 to 17472.

$$x=\frac{-32±\sqrt{18496}}{2\times 16}$$

Take the square root of 18496.

$$x=\frac{-32±136}{2\times 16}$$

Multiply 2 times 16.

$$x=\frac{-32±136}{32}$$

Now solve the equation x=\frac{-32±136}{32} when ± is plus. Add -32 to 136.

$$x=\frac{104}{32}$$

Reduce the fraction \frac{104}{32} to lowest terms by extracting and canceling out 8.

$$x=\frac{13}{4}$$

Now solve the equation x=\frac{-32±136}{32} when ± is minus. Subtract 136 from -32.

$$x=-\frac{168}{32}$$

Reduce the fraction \frac{-168}{32} to lowest terms by extracting and canceling out 8.

$$x=-\frac{21}{4}$$

The equation is now solved.

$$x=\frac{13}{4} x=-\frac{21}{4}$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$16x^{2}+32x=273$$

Divide both sides by 16.

$$\frac{16x^{2}+32x}{16}=\frac{273}{16}$$

Dividing by 16 undoes the multiplication by 16.

$$x^{2}+\frac{32}{16}x=\frac{273}{16}$$

Divide 32 by 16.

$$x^{2}+2x=\frac{273}{16}$$

Divide 2, the coefficient of the x term, by 2 to get 1. Then add the square of 1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}+2x+1^{2}=\frac{273}{16}+1^{2}$$

Square 1.

$$x^{2}+2x+1=\frac{273}{16}+1$$

Add \frac{273}{16} to 1.

$$x^{2}+2x+1=\frac{289}{16}$$

Factor x^{2}+2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+1\right)^{2}=\frac{289}{16}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x+1\right)^{2}}=\sqrt{\frac{289}{16}}$$

Simplify.

$$x+1=\frac{17}{4} x+1=-\frac{17}{4}$$

Subtract 1 from both sides of the equation.

$$x=\frac{13}{4} x=-\frac{21}{4}$$