Solve 15x>120%(5x+1000)

$$15x > 120 \% (5x+1000)$$

Solve for x

$$x>\frac{400}{3}$$

Solution Steps

Reduce the fraction \frac{120}{100} to lowest terms by extracting and canceling out 20.

$$15x>\frac{6}{5}\left(5x+1000\right)$$

Use the distributive property to multiply \frac{6}{5} by 5x+1000.

$$15x>\frac{6}{5}\times 5x+\frac{6}{5}\times 1000$$

Cancel out 5 and 5.

$$15x>6x+\frac{6}{5}\times 1000$$

Express \frac{6}{5}\times 1000 as a single fraction.

$$15x>6x+\frac{6\times 1000}{5}$$

Multiply 6 and 1000 to get 6000.

$$15x>6x+\frac{6000}{5}$$

Divide 6000 by 5 to get 1200.

$$15x>6x+1200$$

Subtract 6x from both sides.

$$15x-6x>1200$$

Combine 15x and -6x to get 9x.

$$9x>1200$$

Divide both sides by 9. Since 9 is positive, the inequality direction remains the same.

$$x>\frac{1200}{9}$$

Reduce the fraction \frac{1200}{9} to lowest terms by extracting and canceling out 3.

$$x>\frac{400}{3}$$