Solve 15C15*9div5+32

$$15C15 \times 9 \div 5+32$$

Evaluate

$$27C_{15}+32$$

Solution Steps

Multiply 15 and 9 to get 135.

$$\frac{135C_{15}}{5}+32$$

Divide 135C_{15} by 5 to get 27C_{15}.

$$27C_{15}+32$$

Differentiate w.r.t. C_15

$$27$$

Steps Using Derivative Rule for Sum

Multiply 15 and 9 to get 135.

$$\frac{\mathrm{d}}{\mathrm{d}C_{15}}(\frac{135C_{15}}{5}+32)$$

Divide 135C_{15} by 5 to get 27C_{15}.

$$\frac{\mathrm{d}}{\mathrm{d}C_{15}}(27C_{15}+32)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$27C_{15}^{1-1}$$

Subtract 1 from 1.

$$27C_{15}^{0}$$

For any term t except 0, t^{0}=1.

$$27\times 1$$

For any term t, t\times 1=t and 1t=t.

$$27$$