Solve for x
x\geq \frac{7}{3}
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15x-10-6x\geq 11
Subtract 6x from both sides.
9x-10\geq 11
Combine 15x and -6x to get 9x.
9x\geq 11+10
Add 10 to both sides.
9x\geq 21
Add 11 and 10 to get 21.
x\geq \frac{21}{9}
Divide both sides by 9. Since 9 is positive, the inequality direction remains the same.
x\geq \frac{7}{3}
Reduce the fraction \frac{21}{9} to lowest terms by extracting and canceling out 3.
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