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15t^{2}-114t+4=0
Substitute t for x^{2}.
t=\frac{-\left(-114\right)±\sqrt{\left(-114\right)^{2}-4\times 15\times 4}}{2\times 15}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 15 for a, -114 for b, and 4 for c in the quadratic formula.
t=\frac{114±2\sqrt{3189}}{30}
Do the calculations.
t=\frac{\sqrt{3189}}{15}+\frac{19}{5} t=-\frac{\sqrt{3189}}{15}+\frac{19}{5}
Solve the equation t=\frac{114±2\sqrt{3189}}{30} when ± is plus and when ± is minus.
x=\sqrt{\frac{\sqrt{3189}}{15}+\frac{19}{5}} x=-\sqrt{\frac{\sqrt{3189}}{15}+\frac{19}{5}} x=\sqrt{-\frac{\sqrt{3189}}{15}+\frac{19}{5}} x=-\sqrt{-\frac{\sqrt{3189}}{15}+\frac{19}{5}}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.